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A.
ip route 10.0.0.0 0.0.0.255 10.1.1.1 255.255.255.0
B.
ip route 10.0.0.0 0 255.255.255.0 10.1.1.1 150
C.
ip route 10.255.255.255 255.0.0.0
D.
ip route 1.1.1.1 0.0.0.0 10.0.0.0
Answer: B The correct syntax for a static route is the ip route command followed by the destination network, mask, next-hop gateway, and administrative distance. Chapter: 4 183. What is the broadcast address of the following IP address? 172.16.10.5 255.255.255.128 A. 172.16.0.255 B. 172.16.10.127 C. 172.16.10.255 D. 172.16.10.0 Answer: B The network block size is 256-128 or 128, so the network boundaries must start at 128 or 0. With a class C address of 172.16.0.0 subnetted this way, the networks are: 172.16.0.0, 172.16.0.128, 172.16.1.0 172.16.1.128 and so on up to 172.16.10.0. So this device is on the 172.16.10.0 network. The next network is 172.16.10.128 and therefore the network broadcast for 172.16.10.0 is 172.16.10.127. Chapter: 4 184. What is the host range of the following IP address? 172.16.10.33 255.255.255.224 A. 172.16.10.32 - 10.63 B. 172.16.10.33 - 10.63 C. 172.16.10.32 - 10.64 D. 172.16.10.33 - 10.62 Answer: D The network block size is 256-224 or 32, therefore the networks start every 32 addresses. The first network is 172.16.10.0, the second at 172.16.10.32, the third at 172.16.10.64 and so on. This host is on the 172.16.10.32 network and the range is .33 through .62 with the broadcast at .63 Chapter: 4 185. Which command will display the configured IP routing protocols? A. show ip protocols B. show protocols C. show ip route |
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